收作业不清楚谁没交，一个一个的数，太麻烦。
😏😏😏
写一个程序搞定他。

# encoding: utf-8
"""
@author: Eden
@contact: .....
@time: 2020/3/26 17:56
@file: homeWork.py
@desc:      作业查收，扫描文件夹，利用正则表达式，匹配唯一id学号
        然后遍历名单，获取未交作业人员
"""
import os
import pandas as pd
import re
import threading
import zipfile
import time


def listdir(path, list_name):
    """
    @param path:  str
    @param list_name: list
    """
    for file in os.listdir(path):
        file_path = os.path.join(path, file)
        if os.path.isdir(file_path):
            # 判断对象是否是一个目录
            # 修改建议，目录直接压缩，判断压缩后的文件是否已经存在。？？？？
            listdir(file_path, list_name)
        else:
            # print(re.findall(r"\d+\.?\d*", file_path))
            # file_path = re.findall(r"\d+\.?\d*", file_path)[0]
            file_path = re.findall(r"\d+", file_path)[0]  # /d匹配数字，+匹配多次
            if len(file_path) != 10:  # 如果学号不是10位数字，代表学号错误。
                print(file_path + "是一个错误的学号")
            # print(file)
            # print(file_path)
            list_name.add(int(file_path))


def reprint():
    set_len = len(unpaid)
    if set_len > 0:
        print("还有%d名同学没有教作业！！" % set_len)
        for index in unpaid:
            print(index, df[index])
    else:
        print("作业已经交齐了。")


if __name__ == '__main__':
    # start = time.clock()
    work_path = r"E:\study\Linux高级运维\作业\Linux高级运维_shell脚本作业_第四次作业"
    work_list = set()
    t = threading.Thread(target=listdir, args=(work_path, work_list))
    t.start()
    # listdir(work_path, work_list)
    excel_path = r"RenYuanMingDan.xlsx"  # 人员名单
    df = pd.read_excel(excel_path, encoding="utf-8", usecols=[u"姓名", u"学号"])
    df = df.set_index([u"学号"])
    df = df.to_dict()
    df = df[u"姓名"]
    t.join()
    unpaid = set(df) - work_list
    reprint()
    # elapsed = (time.clock() - start)
    # print("Time used:", elapsed)

修改版代码：
1、 解决了文件路径带有其他数字的bug。
2、目录不在进行扫描。

# encoding: utf-8
"""
@author: Eden
@contact: .....
@time: 2020/3/26 17:56
@file: homeWork.py
@desc:      作业查收，扫描文件夹，利用正则表达式，匹配唯一id学号
        然后遍历名单，获取未交作业人员
"""
import os
import pandas as pd
import re
import threading
import zipfile
import time


def listdir(path, list_name):
    """
    @param path:  str
    @param list_name: list
    """
    for file in os.listdir(path):
        file_path = os.path.join(path, file)
        if os.path.isdir(file_path):
            # 判断对象是否是一个目录
            # 修改建议，目录直接压缩，判断压缩后的文件是否已经存在。？？？？
            # listdir(file_path, list_name)
            print("目录不做检查")
        else:
            filepath, fullflname = os.path.split(file_path)
            # print(fullflname)
            file_path = fullflname
            try:
                file_path = re.findall(r"\d+", file_path)[0]  # /d匹配数字，+匹配多次
            except IndexError:
                print(file_path, "没有学号")
            if len(file_path) != 10:  # 如果学号不是10位数字，代表学号错误。
                print(file_path + "是一个错误的学号,文件名 ", fullflname)
            # print(file)
            # print(file_path)
            else:
                list_name.add(int(file_path))


def reprint(unpaid):
    set_len = len(unpaid)
    if set_len > 0:
        print("还有%d名同学没有教作业！！" % set_len)
        for index in unpaid:
            print(index, df[index])
    else:
        print("作业已经交齐了。")


if __name__ == '__main__':
    # start = time.clock()
    work_path = r"E:\study\大数据决策\作业\大作业"
    # work_path = r"C:\Users\Eden\Desktop\笔记\自动化运维笔记"
    work_list = set()
    t = threading.Thread(target=listdir, args=(work_path, work_list))
    t.start()
    # listdir(work_path, work_list)
    excel_path = r"RenYuanMingDan.xlsx"  # 人员名单
    df = pd.read_excel(excel_path, usecols=[u"姓名", u"学号"])
    df = df.set_index([u"学号"])
    df = df.to_dict()
    df = df[u"姓名"]
    t.join()
    set_df = set(df)
    # reprint(work_list)
    print_set = set(df) - work_list
    reprint(print_set)
    # elapsed = (time.clock() - start)
    # print("Time used:", elapsed)